Tuesday, June 11, 2013

Some interactions between crowdedness and influences.

Let's start with one of the simplest sets of interactions.  We'll look at squares with three spaces left and a single influence.

X
X
 X

t




t
X
X
X

m




m




b




b










l
c
r















































l
c
r




For each influence, I've color coded the result.


Black is no effect
Green is pair
Blue is deduction

Red is impossible/invalid

So in this first chart we can see that out of six occasions, three have a result and one can never happen in the game.  So 3/5ths or 60% of the time we get at least a pair.

But of course, the "crowd" in the square mighte be in a different configuration.

How about something that looks like this:

X
X
 X

t




t
X
X


m




m
X



b




b










l
c
r















































l
c
r




Here, our results are different.  There are no invalid interactions, and while two of the interactions have no result, two of them (b) will give us a hit, not just a pair.  If 2/3rds of our interactions give us a result here, that's 66%.  

We can create different charts with three spaces, but are they functionally equivalent to this one?







Nothing to do but test it.

X
X


t




t
X
X


m




m
X

X

b




b










l
c
r















































l
c
r



And clearly the answer is no.  We're looking at one result with no influence, but we've raised our pairs to four and reduced our hits to one.  

5/6ths into percentages is more than my brain is up to just now.  But I've got one more chart for us to investigate.













This time, we'll break things up a bit.

X

  X

t




t
X
X


m




m
X

X

b




b










l
c
r















































l
c
r


And we get a similar result.  One dud, one hit, and four pairs.

What makes this arrangement functionally equivalent to the one above it?

Something to think about.

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